00:01
We have here a sample of carbon dioxide host mass is 1 .25 grams of carbon dioxide.
00:17
And this sample is contained in a volume of 750 ml and is at a temperature of 22 .5 .m.
00:32
And is at a temperature of 22 .5.
00:38
Celsius.
00:40
We need to determine the pressure of this sample, gas sample of carbon dioxide.
00:50
So we are going to apply the equation of the ideal gas.
00:55
Pressure times volume equals the number of moles times the constant of the ideal gas times the temperature in kelvin, in degrees kelvin.
01:12
So we need to find the pressure.
01:15
We have the volume.
01:18
We have the amount of the gas, so the mass of the gas, but we don't have the most of the gas.
01:25
So we need to convert these grams to moles.
01:29
Obviously, we have the concern of the ideal gas and we have the temperature that we need to convert to decrease kelvin.
01:37
So let's do the conversions first before we do the substitution and then solving for real.
01:43
Pressure so one one point 25 grams of carbon dioxide must be divided by the molar mass of carbon dioxide the molar mass of carbon dioxide is one times twelve the atomic weight of carbon plus that's 12 plus two times 16 the atomic weight of oxygen and this is grams per mole this is how we convert these grams to moles the grams will cancel and we're gonna have mole which is in the numerator of a numerator in the denominator of a denominator and therefore it's gonna be a become a numerator so we need to divide 1 .25 by 44 12 plus 32 is 44 so 1 .25 divided by 44 and we get 0 .084 moles of carbon dioxide.
03:07
Now we convert the temperature.
03:10
The temperature in kelvin's so this is n number of moles.
03:16
The temperature in kelvin's will be the temperature in celsius plus 273 and the answer is to 22 .5 plus 273 is 22 .5 plus 273 is 295 .5 degrees kelvin.
03:44
Okay...