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A 13.0$\%$ solution of $\mathrm{K}_{2} \mathrm{CO}_{3}$ by mass has a density of 1.09 $\mathrm{g} / \mathrm{cm}^{3} .$ Calculate the molality of the solution.

1.08 $\mathrm{m}$

01:45

Aadit S.

Chemistry 102

Chapter 11

Solutions and Colloids

Solutions

Rice University

Drexel University

University of Maryland - University College

University of Kentucky

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morality is defined as the moles of solute per kilogram of just the solvent. So if we have a solution that is 13 by mass potassium carbonate. this means that if we have 100 g sample, 13 g would be potassium carbonate And 100 -13 would be the mass of the water. Yeah, to calculate morality, we then need to convert the mass of the salute potassium carbonate into moles potassium carbonate and we need to convert the mass of water into kilograms of water. We can convert the mass of water into kilograms by dividing by 1000 I'm sorry, by multiplying By 1000. So that the g of water cancel and we're left with kg of water in the denominator. We can then convert the mass of potassium carbonate into molds potassium carbonate in our numerator by dividing by the molar mass of potassium carbonate. This calculation then gives us molds potassium carbonate per kilogram water, which is morality at a value of 1.8 The density is not required

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