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A 13.5 -foot-long, nearsighted python is stretched out perpendicular to a plane mirror, admiring its reflected image. If thegreatest distance to which the snake can see clearly is 28.0 $\mathrm{ft}$ ,how close must its head be to the mirror for it to see a clearimage of its tail?

Thus, the distance from the head of the python to the mirror is $\overline{7.25 \mathrm{ft}}$

Physics 103

Chapter 26

Geometrical Optics

Wave Optics

Cornell University

Rutgers, The State University of New Jersey

Hope College

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question 11 says. We have a 13.5 foot long snake who's looking into a merry stretched out perpendicular to the mirror, and the snake is nearsighted and can only see 28 feet. How close must have had been. The me referred to see a clear image of its tail. Now our object distance. That's this. Our object is over. Here are images over here, so the green snake is the snake that's looking into the mirror. Blue snake is its reflection in a plane near the distance between the object and the mere dio object distance is the same as the image distance for the distance where the image appears in the mirror. Now that means if the snake is X meters away from the mirror, then the reflected image appears. Acts meters away from from them here, which means this whole distance the snake is looking before it starts to see. Its reflection is two X Um, now, if its tail is 13.5 meters away from it over here, then it's also 13.5 meters away from it over here, which means the snake can see a total distance of 28 feet. Um, and of that 28 feet, we have this two x distance, Um, which is however far the snake is from the mere on one side. And however far the snake is from your on the other side and then minus 13.5 feet because that's how far it is to the tail on this is zero, right? That so the maximum distance we can see is 28 or if you'd like 28 feet, is 13.5 feet, plus the two acts there. And so all we have to do is solve this for X. So if I subtract that 13.5 from both sides to get 14.5 equals two X. But we're interested in how far from the mere which is only one X. So we're gonna divide both sides of this by two, and we see 7.25 feet is the maximum distance from the mere

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