00:04
For this question, we're going to assume that we have one liter present of solution.
00:14
We're told that we have 1 .37 molar or moles per liter of the citric acid.
00:32
So if we have one liter, that means we have 1 .37 moles of the citric acid.
00:40
Converting this to grams will yield 263 grams of the citric acid.
01:06
We're also told that this is in water and we are dealing with one liter.
01:14
One liter would be equivalent to a thousand milliliters times the density 1 .10 grams per milliliter given in the question would yield 1 ,100 grams altogether, which means that if 263 grams are citric acid and 1 ,100 grams would be the total, if we do the subtraction here, that would yield 837 grams of water being present.
01:52
From these numbers, we'll first calculate the mass percent, which will be 263 grams of the citric acid, over 1 ,100 grams total.
02:10
This should be 1 ,100 grams in the denominator here, times 100 percent to give a mass percent of 23 .9 percent...