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Scem sheld university physics volume 2 global edition.
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Chapter 31 image and optical instruments problem number 39 a 14mm height object is 11 cm from a concave mirror with focal length 16 cm.
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Here we must have to find that where is the image, height of the image, as well as what kind of image is that, what type of image is that formed? so here the given are given data are h .o, that is height of the object is equal to 14 millimeter.
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Focal length of the concave mirror f is equal to minus 16 centimeter.
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Distance of the object.
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U is equal to minus 11 centimeter we have to find v is equal to and height of the image h i and type of the image so in the first question we must have to use the mirror formula that is 1 by v plus 1 by u is equal to 1 by f.
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So here we have to find 1 by v equals to 1 by f minus 1 by u.
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1 by f minus that's equal to 1 by minus 16 minus 1 by 11 minus 1 by 11 that's equal to 1 by 11 which gives us 6.
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16 minus 11 divided by 17 .16...