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A 1450-kg submarine rises straight up toward the surface. Seawater exerts both an upward buoyant force of 16 140 N on the submarine and a downward resistive force of 1030 N. What is the submarine’s acceleration?

0.621 $\mathrm{m} / \mathrm{s}^{2}$

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Rutgers, The State University of New Jersey

University of Michigan - Ann Arbor

University of Washington

Hope College

to serve this question. All we have to do is apply Newton's second law. There are only forces acting on the vertical axis, So let me choose these to be the positive direction off that access. Then the net force on that access. Is it close to the mass of the simmering times, its acceleration. So that celebration of this premiering is it close to the net force divided by the mess. But the net force is composed by three forces. The bullet wound up force which points the positive direction miners the Yuyuan Down Force, which points the negative direction. My news. The weight force which outside points to the negative direction and these always divided by the mass off the simmering. Now remember that the weight force is given by the mass times acceleration of gravity, which is approximately 9.8 meters per second squared. Then the acceleration off that submarine is given by 16140 miners 10 30 minus 14 15 times 9.8 divided by 14 15 Then the acceleration is approximately 0.6 to 2 meters per second squared

Brazilian Center for Research in Physics