00:01
For this problem, let's first draw a vector diagram indicating our velocities.
00:07
So v -a is the velocity of the wedge as it moves to the right.
00:14
V -b is the velocity of block b down the slope.
00:21
And the resultant velocity v -b -slash -a, which is the velocity of b relative to a, is simply the resultant of those two vectors.
00:34
So from here we can see that vector vb is equal to vector va plus vector vba.
01:02
So vector mathematics tells us that vb is equal to va plus vba and we know that this angle is 30 degrees.
01:12
So from the law of cosines, we can tell the following.
01:21
The law of cosines tells us that vb squared is equal to v a squared plus vb a squared minus 2 v a, v .a relative to a, multiplied by the cosine of 30 degrees.
01:49
And we'll call this equation one.
01:51
So we'll call upon this equation later.
01:54
Now we'll use the principle of impulse and momentum.
02:09
So we'll use the principle of impulse and momentum to calculate the velocities of the wedge va and the velocity of b relative to a.
02:27
So the principle of impulse and momentum tells us that the sum of the momentum of each of the particles before the event plus the sum of the impulses on the system is equal to the final momentum of the system.
02:52
So essentially momentum is conserved.
02:57
So let's draw a diagram of our situation.
02:59
We have wedge a and block b initially at rest.
03:11
And then the impulses acting on this system are as follows.
03:30
The normal force times t, the normal force acting on the wedge.
03:38
In the opposite direction, we have the weight of block a times t or wedge a.
03:47
And for b, the impulse is its weight times t.
03:55
And the final scenario is that in which the wedge moves off with momentum m .a.
04:08
Va.
04:09
So its final velocity is va.
04:13
The block moves with the wedge with momentum mb va.
04:23
So it's moving at the same velocity that the wedge is moving with.
04:28
And at the same time, it moves down the slope with momentum...