00:01
Here, the moment of inertia for the system would be equaling the moment of inertia for the rod itself plus the moment of inertia for the ball.
00:09
Moment of inertia for a rod, one third, multiplied by the mass of the rod, multiplied by the length of the rod squared, plus the mass of the ball times the length squared.
00:23
And so we can actually find the moment of inertia for the system.
00:26
This would be equaling then one third, multiplied by 0 .200 kilograms, multiplied by 0 .15 meters quantity squared, plus 0 .020 kilograms, multiplied by 0 .15 meters quantity squared.
00:49
And this is giving us 1 .95 times 10 to the negative third kilograms meters squared.
00:58
To find the y position of the center of mass, this would be equalling to then the weighted mean essentially from the pivot point to find the y position.
01:13
So we have 0 .02, 0 .200 kilograms multiplied by 0 .15 meters divided by 2 away from the axis of rotation.
01:29
This would be plus 0 .020 kilograms, and this would be multiplied by 0 .15 meters...