The ball contains \(4.00 \times 10^{8}\) excess electrons. The charge of one electron is approximately \(-1.60 \times 10^{-19} \, \text{C}\). Therefore, the total charge \(q\) on the ball is:
\[ q = (4.00 \times 10^{8}) \times (-1.60 \times 10^{-19} \, \text{C}) =
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