00:01
So we've told we have a uniform ladder that weighs 500 newtons that's against a frictionless wall.
00:08
The ladder makes an angle here of 60 degrees with the horizontal.
00:14
And we want to find the vertical force and vertical and horizontal forces on the ground.
00:21
If there's a 800 newton firefighter that's climbed four meters up the ladder.
00:29
And then we want to figure out if the ladder is on the verge of slipping when the firefighter is at nine meters up the ladder what is the friction coal friction all right so we got the weight of the firefighter the weight of the ladder we know that the ladder was 15 meters long so we know that the center of mass is seven seven and a half meters up um from the ground here and the firefighter initially is four meters from the base of the ladder.
01:05
So if we sum forces in the vertical direction, we find that n1 has to offset the mass of the firefighter and the mass of the ladder, and so that means that that is 1 ,300 newtons.
01:24
Now, if we take moments about, about this point here and so that is our point not so we that the sum of the moments better be zero for if this thing is in equilibrium and so we can see that m .g creates a negative moment okay if we're saying counterclockwise is positive mg creates a negative moment and the moment arm is here is d1 and this is also d1, cosine of theta...