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For this problem on the topic of conservation of energy, we are told that a 1 .5 kilogram snowball is thrown from a cliff that is 12 .5 meters high, with an initial velocity that is 14 meters per second directed at 41 degrees above the horizontal.
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We want to find the work done on the snowball by the gravitational force during its flight to the ground below the cliff.
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We want to find the change in gravitational potential energy of the snowball earth system during its flight, and we want to know the.
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Value of the gravitational potential energy as the snowball reaches the ground.
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Now the force of gravity is constant, so the work done, w is equal to f .d, where f is the force and d is the displacement.
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Now, the force is vertically downward and has magnitude mg, where m is the mass of the snowball.
00:57
And so the expression for the work reduces to w is equal to mg, h.
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Where h is the height through which the snowball drops.
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And so the work done by gravity is equal to mgh, where the mass of the snowball is 1 .5kg times 9 .8 meters per square second times a vertical height of 12 .5 meters...