00:01
So this question belongs to the magnetic force in which we have magnetic field b equals to 1 .50 tesla in the northeast direction.
00:09
And we have to determine the magnitude of magnetic force and as well as the direction on the charge q equals to 0 .50 column that is moving speed p equals to 10 meter per second and for the part a it is moving in the north direction.
00:30
So, velocity is in the north direction.
00:32
So we can write that the magnitude of force b, f, this will be equals to qvb.
00:38
So substituting values, so we get 0 .50 multiplied by 10, multiplied by 1 .50.
00:45
So from here we get magnitude of the force f, this is equals to 5 .30 newton.
00:52
So for the when the particle is moving in the north direction and magnetic field is in the north -east direction, the magnetic force, this will be equals to 5 .30.
01:04
This is the magnitude and the force will be in the vertically down direction.
01:10
So, vertically down direction will be the direction of force.
01:16
This become the answer for the part a.
01:18
Now moving to the part b in which the velocity is in the east direction...