(b) To find the average power, we can use the formula:
$P_{avg} = \frac{W}{t}$
Since the work done is equal to the change in kinetic energy, we have:
$P_{avg} = \frac{300,000 \mathrm{~J}}{30 \mathrm{~s}} = 10,000 \mathrm{~W}$
So the average power required
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