Question
A $160-\mu \mathrm{F}$ capacitor charged to $450 \mathrm{V}$ is discharged through a $31.2-\mathrm{k} \Omega$ resistor. (a) Find the time constant. (b) Calculate the temperature increase of the resistor, given that its mass is $2.50 \mathrm{g}$ and its specific heat is $1.67 \mathrm{kJ} / \mathrm{kg} \cdot^{\circ} \mathrm{C}$ noting that most of the thermal energy is retained in the short time of the discharge. (c) Calculate the new resistance, assuming it is pure carbon. (d) Does this change in resistance seem significant?
Step 1
In this case, we have $R = 31.2 \, k\Omega$ and $C = 160 \, \mu F$. Therefore, the time constant is given by: \[\tau = RC = (31.2 \times 10^3 \, \Omega) \times (160 \times 10^{-6} \, F) = 4.992 \, s\] Show more…
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A 160 - $\mu$ F capacitor charged to 450 V is discharged through a 31.2 -k $\Omega$ resistor. (a) Find the time constant. (b) Calculate the temperature increase of the resistor, given that its mass is $2.50 \mathrm{g}$ and its specific heat is $1.67 \frac{\mathrm{kJ}}{\mathrm{kg} \cdot^{\circ} \mathrm{C}}$ noting that most of the thermal energy is retained in the short time of the discharge. (c) Calculate the new resistance, assuming it is pure carbon. (d) Does this change in resistance Seem significant?
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