00:01
In this problem, we are told that a sample of gold is dropped into a certain amount of water and that this raises the water temperature and that they come to an equilibrium final temperature of 27 .5 degrees celsius.
00:17
So we know that the cue or the heat that goes in to the water must be equal to the heat that comes out of our sample of gold.
00:32
And so for equivalencies, we can just do, we know that q is equal to mass times specific heat, times change in temperature.
00:47
And so we can set the mc delta t of the water equal to the mc delta t of our gold sample.
00:56
And so let's do that really quickly.
00:58
We know that the gold is 100.
01:01
I'll label this very quickly.
01:05
So we don't get confused here.
01:07
Gold at the top.
01:10
On one side and water on the other.
01:16
So we have 182 grams of gold.
01:21
The specific heat, given in the problem, is 0 .128 joules per gram kelvin.
01:37
And then our change in temperature, we don't know the change in temperature, but we do know the final temperature.
01:45
So the final temperature given in the problem is 27 .5.
01:52
You know what? i'm taking up a little too much room here, so we'll write these vertical to each other...