00:01
For this problem on the topic of thermodynamics, we are told that a man of height 1 .88 meters, mass 80 kilograms, body surface area, 2 .1 square meters, and his skin temperature of 30 degrees celsius converts 80 % of the food calories he consumes to heat, whereas the rest goes to mechanical energy.
00:20
We want to know how many food calories he should eat per day to keep his body temperature constant if he is in a room at 20 degrees celsius and only uses heat through radiation.
00:30
And we also want to know if this number seems reasonable.
00:35
Now, given in the problem, we have the net rate of radiation to be the radiation rate from his body minus the radiation rate from the air.
00:50
So the rate of net energy change is per unit time is equal to the radiation power from the body, minus the radiation power from the a, which means that the net energy change is equal to p body minus pa times the time of delta t.
01:24
And so this energy is 0 .8 times x into 4 ,186 joules per kilo.
01:40
Kilo calorie where we want to solve for x and this is equal to the emissivity e times the stephan bolzman constant sigma times a times the temperature of the body to the power four minus e sigma a times the temperature of the air to the power of four or times doubt t which we can write as the temperature of the body to the power four minus the temperature of the body to the power four minus the of a to the power 4, all multiplied by e sigma delta t...