The heat lost by the copper will be equal to the heat gained by the water. This can be expressed as:
\[m_{c}c_{c}(T_{i_{c}}-T_{f}) = m_{w}c_{w}(T_{f}-T_{i_{w}})\]
where \(m_{c}\) and \(m_{w}\) are the masses of the copper and water respectively, \(c_{c}\) and
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