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A 2 kg rock is dropped off a cliff with a height of 20 $\mathrm{m}$ . What the speedof the rock at the bottom of the hill?(A) 10 $\mathrm{m} / \mathrm{s}$(B) 14 $\mathrm{m} / \mathrm{s}$(C) 20 $\mathrm{m} / \mathrm{s}$(D) 40 $\mathrm{m} / \mathrm{s}$
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Chapter 4
Practice Test 4
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the speed off the rocks at the bottom of the can be calculated using a off conservation of energy. So the potential energy is converted into the can take energy off the rock when it falls through the height. The potential energy we have here is an n g H and the kind of energy and ruthless one or two Em uh, we were fined over lost tvs square. Then we console for we f here can selling out him, which is two turns off squirreled over gh. So, um, two times off, 10 here. Traditional exclusion times the height of the clip which is 20 and taking a square root off this number. He's US 22 per second. So our answer off this our answer is option of mercy.
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