00:01
Hi, everybody.
00:01
So we need to find the exit, moist air, humidity ratio and the flow rate of liquid water.
00:07
Find also the dry air temperature of t1.
00:10
Okay.
00:11
So the humidity ratio at exit is going to be represented with the humidity ratio equation, so pb minus pb.
00:24
So here we have 0 .622 times 1 .1 .1 .2.
00:33
2276 divided by 100 minus 1 .2276 and we get 0 .00773 and that is your exit your community ratio at exit and now we can find with a continuing continue i cannot pronounce that word today the continue equation okay i was going to say that because apparently it cannot say continuity.
01:07
And you know i'm mispronouncing it, so i apologize.
01:12
M liquid, and that's air and that's liquid, okay? and this is going to be equal to m of air, one plus the humidity ratio.
01:23
And we're just going to keep going, and we get m of the liquid equals m of the humidity.
01:29
And we get two times 0 .000773 equals 0 .0154, 6 kilograms per second.
01:46
And that is your mass of the liquid.
01:49
Now we can do the energy equation.
01:52
And i'll put that here.
01:53
The energy equation.
01:57
Okay.
01:58
That's a q.
02:00
And for that, we have m -a -h -a -1 plus m.
02:06
Oops, m.
02:07
Oops, i was trying to write h and m at the same time.
02:11
M of liquid, okay, times h -f equals m -a, oops, equals m -h -a2 plus w -2, h -g -2...