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A 2 $\mathrm{kg}$ object is tied to a machine with a 5.5 $\mathrm{m}$ long string. The machine whirls the object in a horizontal circle at various speeds according to the speed-versus-time graph below. What is the magnitude of the centripetal acceleration of the 2 $\mathrm{kg}$ object at $t=3 \mathrm{s} ?$(A) $\mathrm{om} / \mathrm{s}^{2}$(B) 8 $\mathrm{m} / \mathrm{s}^{2}$(C) 16 $\mathrm{m} / \mathrm{s}^{2}$(D) 32 $\mathrm{m} / \mathrm{s}^{2}$

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Chapter 13

Practice Test 3

Section 1

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2 kg object is tied to a m…

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Centripetal force: $F=m v^…

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An object of mass $m$ is t…

Hi in the given problem mass of the object He's given us M is equal to two kg and lamp of this ring with which the subject has been tied Is given as. L is equal to 0.5 m now. As But the good given here the speed of the object, the linear speed of the object which is moving in a circle act at a time Equals 2 3 seconds Is four m/s. Hence at that instant. Century petal acceleration of the object will be using expression for scientific collaboration, which is we square by. Are there vistas speed of the object in circular motion? And our means radius. So here this length of the string will behave like the radio. So this is we score by L. For me this is four meter per second to the whole square divided by length which is 0.5. So here it comes out to be a C. Is going to 16 divided by 0.5, which comes out to be 32 m per second squared. Hence you can say here our option D. Is correct. Thank you.

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