Question
A $2 \mathrm{~m}$ -long string fixed at both ends is set into vibrations in its first overtone. The wave speed on the string is $200 \mathrm{~m} \mathrm{~s}^{-1}$ and the amplitude is $0 \cdot 5 \mathrm{~cm}$. (a) Find the wavelength and the frequency. (b) Write the equation giving the displacement of different points as a function of time. Choose the $X$ -axis along the string with the origin at one end and $t=0$ at the instant when the point $x=50 \mathrm{~cm}$ has reached its maximum displacement.
Step 1
Therefore, the wavelength $\lambda$ would be equal to twice the length of the string. So, we have \[\lambda = 2L = 2 \times 2 \, \text{m} = 4 \, \text{m}\] Show more…
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