00:02
Hi, in the given problem, there is a spider in front of the wall.
00:10
So this is the wall.
00:12
This is suppose the spider in front of this wall.
00:20
The diameter of this spider is 2 .0 centimeter and its distance from the wall is given as 2 .0 .0.
00:50
Or we can say this is 200 cm.
00:55
We have to obtain an image of this spider over the wall for which we will use a convex lens which will form a real image of this spider over the wall.
01:10
So here this distance of the spider up to the lens will be behaving like the object distance for this convex lens.
01:21
Means p and here this distance of the lens from the wall will be behaving like the image which stands cube hence we can say p plus q is equal to 200 centimeter now this is also given that the image of the spider the diameter the image the diameter of the image of the spider is half to that of the spider itself means the linear magnification has been given as half.
01:53
And we know the linear magnification is given as the ratio of the distance of the image to the distance of the object.
02:01
Hence, using that, we conclude that this p is equal to twice of q...