00:01
Here in this question, the heat lost by copper is equal to the heat gained by water and iron 4.
00:11
The net heat flow is 0.
00:16
Therefore, qc plus qw plus qi equals to 0.
00:29
So we can write this as mw multiply by cw multiplied by ef minus t -i plus mc multiply by c -c multiply by t -f -e -c -m -c -multiply t -f -e -c -i plus m -i -c -c -c -multiply t -f -f minus e -c -c -i plus m -i -c -c -c -i multiplied by tf minus t -i equals to zero.
01:11
Now here, mw is actually the mass of the water.
01:15
Mc is the mass of the copper.
01:18
Mi is the mass of the iron.
01:21
Here is initial temperature of water and iron pore.
01:25
And cw is the specific heat of water, whereas c .c is the specific heat of copper and ci is the specific heat of iron pore.
01:37
Now we rearrange this above equation for t f, thus the final temperature of the system can be expressed as t f equal m i c i plus m w c w multiply by t i plus m c w multiply by t i plus m c c .i.
02:13
Divided by m .i .c .i...