The curve is a triangle with base $S_s = 20.0 \,\text{J/K}$ and height $T_s = 400.0 \,\text{K}$. The area of the triangle is:
$Q = \frac{1}{2} \cdot S_s \cdot T_s = \frac{1}{2} \cdot 20.0 \,\text{J/K} \cdot 400.0 \,\text{K} = 4000 \,\text{J}$
So, the energy
Show more…