00:01
In this question we are given two capacitors, so c1 being 2 ferrets and c2 being 7 .5 microferrets.
00:22
We also have resistors r1 being 25 oms and r2 being 100 ,000 oms.
00:39
We want to consider what are the four possible rc time constants from having the capacitors and resistors in either in series or parallel.
00:48
So the first possible scenario is all of them are in series with each other.
00:56
So the total capacitance, c, would be equal to some of the reciprocals inverse.
01:06
This is how we add capacitors in series.
01:10
So this would be 1 .5x2 plus 1 .25 by 7 .5.
01:23
We will get 7 .4997 times 10 .4 minus 6 ferrets, right, very close to c2 because c2 is very small.
01:37
Then the overall resistance are, right, in series will be just taking 25 plus 100 ,000.
01:45
Which is approximately just 100 ,000 oms if you are to be accurate then we get 100 ,000 and 25 oms now the rc time constant just multiply these two values together get 0 .75 seconds the second case would be that both the capacetors and resistors are in parallel now for the capacitance, when they are in parallel, we add them up like resistors in cvs, so we just c1 and c2.
02:38
So this will be approximately 2 ferrets, because the c2 is really small...