00:01
By saying that dq divided by d t in is equal to q in times dv d t in so solving we have dkd t in is equal to in is equal to q one times r one so basically we're calculating the rate of input and output in pounds per gallon and then it's doing the same thing but for the output.
00:36
So we have dqdt out is equal to qr2 divided by v.
00:48
So the next thing i'm going to do is we're going to solve for v.
00:53
So we have v is equal to vi plus dvdt times t.
01:02
And then we can solve for this to get dvdt is equal to r1 minus r.
01:08
Or v is equal to v0 plus r1 minus r2 times t applying equation the equation we get dq d t is equal to dk d t in minus d q d t out so this is just equal to doing what we did before q 1 r1 minus q 2 divided by v.
01:42
And since we have an equation for v, we can just substitute that in to get minus qr2 divided by v0 plus r1 minus r2 times t, which can be rearranged in order to get dqdt plus qr2 plus qr2.
02:11
Divided by v0 plus r1 minus r2 times t is equal to q1 r1.
02:23
So now we will begin solving the required.
02:26
So if we have vf is equal to vi, vi plus r1 minus r2 times t...