00:01
A 2 .00 kilogram block is placed on top of a 5 .00 kilogram block as shown.
00:09
Our coefficient of friction between the 5 kilogram block and the surface on which it is sliding is 2 .00.
00:18
The horizontal force is applied to the 5 is applied to the 5 kilogram block.
00:23
A, we're asked to draw a free body diagram for each block.
00:32
Okay, that i can do.
00:36
Free body diagram for each block.
00:43
So first, i've got a two kilogram block, and this will have a downward force of 19 .6 newtons, a normal force of 19 .6 newtons, and a force here of, i believe this will just be x, and then it'll be static friction.
01:17
Then my 5 kilogram block, that'll have a, let's make that a little bit more legible, we'll have my gravity of 49 .0.
01:38
It'll have a force of this.
01:43
This will have a friction force here.
01:49
It'll be kinetic.
01:52
It'll have a friction force here.
01:58
It'll have a 19 .6 force down here.
02:05
And then an n2 right here.
02:08
Okay.
02:12
Now for our second part of this, we're asked to calculate the magnitude of the force.
02:21
Let me go to my next page.
02:33
To pull both blocks right at 3.
02:51
I think it's 3 .00.
02:56
Yes.
03:00
Meters per second squared.
03:04
Okay.
03:08
So let's do this.
03:15
Hmm.
03:18
So let's do m1, those 2 .00 kilograms.
03:27
M2 equals 5 .00 kilograms.
03:34
So our mass total is 7 .0...