00:01
So the equations for the natural frequency of vibration were derived in a separate problem, and so we can go ahead and write those down.
00:08
So the operating speed of the turbine would be w0 is equal to 2 ,400 times 2 pi over 60, and that is equal to 251 .328 radiance per second.
00:26
And we need to satisfy these three, i guess, requirements.
00:31
So w -n -axial is equal to g -l -a -e divided by w -a -a -times -l -m -a.
00:43
All of that to the one -half power must be greater than or equal to w -0.
00:49
W -n of transverse would be 3e -i's l -quived g divided by w -a -cubed, l -m -a -cubed.
01:07
All of that to the one half power must be greater than equal to w -0.
01:13
And then lastly, w -n of circumferential would be g -j over j -0 times 1 over a plus 1 over l -minus a...