Question
A 20.0 -L tank contains $4.86 \times 10^{-4} \mathrm{kg}$ of helium at $18.0^{\circ} \mathrm{C} .$ The molar mass of helium is 4.00 $\mathrm{g} / \mathrm{mol} .$ (a) How many moles of helium are in the tank? (b) What is the pressure in the tank, in pascals and in atmospheres?
Step 1
- Given mass of helium: \(4.86 \times 10^{-4} \, \text{kg}\). - Convert to grams: \(4.86 \times 10^{-4} \, \text{kg} \times 1000 \, \text{g/kg} = 0.486 \, \text{g}\). Show more…
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A $20.0 \mathrm{~L}$ tank contains $4.86 \times 10^{-4} \mathrm{~kg}$ of helium at $18.0^{\circ} \mathrm{C}$ The molar mass of helium is $4.00 \mathrm{~g} / \mathrm{mol}$. (a) How many moles of helium are in the tank? (b) What is the pressure in the tank, in pascals and in atmospheres?
A 20.0-L tank contains $4.86 \times 10{^-}{^4}$ kg of helium at 18.0$^\circ$C. The molar mass of helium is 4.00 g/mol. (a) How many moles of helium are in the tank? (b) What is the pressure in the tank, in pascals and in atmospheres?
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$\bullet$ A 20.0 $\mathrm{L}$ tank contains 0.225 $\mathrm{kg}$ of helium at $18.0^{\circ} \mathrm{C}$ . The molar mass of helium is 4.00 $\mathrm{g} / \mathrm{mol} .$ (a) How many moles of helium are in the tank? (b) What is the pressure in the tank, in pascals and in atmospheres?
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