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Question number 68, the free body diagram of the beam is like this.
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At point a, the reaction is ra.
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At point b, the reaction is rb.
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Point a is 3 meters from the left end.
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The weight is acting mg, 5 meters from the point b.
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And at the point d, the unknown weight is w.
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This distance is 7 meters and this distance is also 5 meters.
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So now to find the unknown weight, we will take the tors of forces about the point b and at the point of tipping, ra is equal to 0.
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So taking the tors, m g into 5 is equal to w into 5.
01:56
Mg is given as 550 newtons.
01:59
So w will also become 550 newton...