Given that the force is $F(t)=(6.00 \, \mathrm{N/s^{2}}) t^{2}$ and the mass is $2.00 \, \mathrm{kg}$, we can calculate the acceleration as $a(t) = \frac{F(t)}{m} = \frac{(6.00 \, \mathrm{N/s^{2}}) t^{2}}{2.00 \, \mathrm{kg}} = 3.00 \, \mathrm{m/s^{4}} t^{2}$.
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