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Welcome.
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Today we'll be talking about the center of motion and momentum.
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So first let's just draw two separate diagrams of the problem and with a small cartesian plane.
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So we know the x and the y.
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Remember that x is also i and y is j.
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So from here this is the first object and this is the second object.
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And i've broken a down.
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Into the components along x and along y so along i and along j and from there we can do our equation vcm the velocity center of mass is equal to the sum of the masses times the velocity divided by the total mass so we'll have that bcm is equal to the sum of the mass and velocity so so the first one is 2 and we're multiplying it in unit vector notation.
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So we'll have 2 i minus 3 j plus 3 kilograms 1 meter per second i plus 6 meters per second j and everything will be divided by the total mass which is 2 plus 3 which is 5.
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So vc mc is equal to 4i plus 3i from here this will be 7i 7i and minus 6 j plus 18 j this will be equal to 12 j positive divided by 5 and remember the jes get added with the j's and i's with the eyes with the eyes so we'll be left with 7i plus 12 j divided by 5.
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So dividing each one by 5 will end up that the velocity center of mass will be equal to 1 .4 along the i plus 2 .4 along the j direction...