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A 2.20$\mu \mathrm{F}$ capacitor is connected across an ac source whosevoltage amplitude is kept constant at $60.0 \mathrm{V},$ but whose frequency can be varied. Find the current amplitude when the angular frequency is (a) $100 \mathrm{rad} / \mathrm{s} ;$ (b) $1000 \mathrm{rad} / \mathrm{s} ;$ (c) $10,000 \mathrm{rad} / \mathrm{s}$ .

a) 0.0132 $\mathrm{A}$b) $=1.32 \mathrm{A}$c) 0.132 $\mathrm{A}$

Physics 102 Electricity and Magnetism

Chapter 22

Alternating Current

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Electromagnetic Induction

Hope College

University of Sheffield

McMaster University

Lectures

04:44

Alternating current (AC) is an electric current which periodically reverses direction, in contrast to direct current (DC) which flows only in one direction. Alternating current is the form in which electric power is delivered to businesses and residences, and it is the form of electrical energy that consumers typically use when they plug electrical appliances into a wall socket. A common source of DC power is a battery cell in a flashlight. The abbreviations AC and DC are often used to mean simply alternating and direct, as when they modify current or voltage.

11:31

In electrical engineering, a direct current (DC) circuit is an electrical circuit operating with a constant voltage (or current), as opposed to alternating current (AC) circuits. Direct current may flow in a conductor such as a wire, but can also flow through semiconductors, insulators, or even through a vacuum as in electron or ion beams.

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to answer this problem, we're going to need that. The current amplitude is related voltage in the reactant sw by this formal, and the reactant CE is equal to one over they or frequency times, the capacitance. And so plugging this into here gives a formula for the current amplitude in terms of the angular velocity. And so it's be Omega Psi. And so if Omega's Eagle 200 under radiance for second, then playing all these other things gives a current amplitude of 0.132 appears So now notice that the current amplitude is proportional to the your frequency by this warm. So if we multiply the angler frequent, then you're frequency by 10. All right, we'll divide by 10. There were also going to multiply this by 10. And so when we do that, we get that the current Antunes is 0.132 amperes. And now if Omega gets multiplied by 10 again, so now it's 10,000 we're gonna multiply this again. And when we do that, we get 1.32 amperes and so that complete support

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