00:01
Calculate the current which passes through each resistance.
00:05
So for the simplicity, let's label resistances as r1, r2, r3, r4, and r5 respectively.
00:17
And now we have to draw the equivalent circuit.
00:22
So let's presume that current passes from a to b.
00:28
In this scenario, the equivalent circuit would look like the following so r1 is in series with the section which is r2 and r3 which are in parallel with r4 and additionally it's all in series with r5 and it's all connected to the battery with the voltage of with the emf of 24 volts so let's calculate the total resistance of this circuit.
01:21
So total resistance of this circuit equals to r1 plus r5 plus rx, where rx is a resistance of the middle section.
01:35
So now we have to calculate rx.
01:43
Rx, yeah, 1 over rx equals to 1 over r4 plus, plus 1 over r2 plus r3 because r2 and r3 are connected in series.
02:06
And r4 is in parallel to r2 and r3.
02:11
So now let's modify this expression a little bit.
02:29
So rx, the resistance of the middle part equals to r4, multiplied by r2 plus r3.
02:38
Divided by the sum of these resistances.
02:45
So now we can calculate the total resistance.
02:50
It equals to r1 plus r5 plus this fraction.
03:08
Let's do this calculate.
03:10
Yeah, let's calculate total resistance numerically.
03:14
So it equals to 1 om plus 3 oms.
03:35
Plus the fraction which is 12 oms multiply by the sum of 8 and 16 oms and it's divided by the sum of all these three resistances.
04:12
So let's complete this calculation.
04:37
So the sum equals to 12 obs...