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A 25 -kg object is being lifted by pulling on the ends of a1.15 -mm-diameter nylon cord that goes over two 3.00 -m-highpoles that are 4.0 $\mathrm{m}$ apart, as shown in Fig. $90 .$ How highabove the floor will the object be when the cord breaks?
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Physics 101 Mechanics
Chapter 12
Static Equilibrium; Elasticity and Fracture
Equilibrium and Elasticity
Cornell University
Rutgers, The State University of New Jersey
Hope College
Lectures
04:12
In physics, potential energy is the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors. The unit for energy in the International System of Units is the joule (J). One joule can be defined as the work required to produce one newton of force, or one newton times one metre. Potential energy is the energy of an object. It is the energy by virtue of an object's position relative to other objects. Potential energy is associated with restoring forces such as a spring or the force of gravity. The action of stretching the spring or lifting the mass is performed by a force which works against the force field of the potential. The potential energy of an object is the energy it possesses due to its position relative to other objects. It is said to be stored in the field. For example, a book lying on a table has a large amount of potential energy (it is said to be at a high potential energy) relative to the ground, which has a much lower potential energy. The book will gain potential energy if it is lifted off the table and held above the ground. The same book has less potential energy when on the ground than it did while on the table. If the book is dropped from a height, it gains kinetic energy, but loses a larger amount of potential energy, as it is now at a lower potential energy than before it was dropped.
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A 25-kg object is being li…
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02:13
A 25 -kg object is being l…
05:04
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04:29
A $5.0$ -kg mass hangs at …
04:36
A cord passing over a fric…
02:43
In Fig. $4.44,$ two blocks…
03:02
An object with mass $m_{\m…
01:32
Find the minimum diameter …
04:57
A $4.0 \mathrm{kg}$ mass i…
03:08
In Fig. $4.46,$ two blocks…
05:25
A pulley has a moment of i…
So for the first part, we have this diagram and we're trying to find essentially the force tension. So we can say that the force tension over A will be equal to the tensile strength. And we know that then from that equation, the force tension would be equal to the area times attention, all strength. And this would be equal to high times 1/2 times the diameter 1.15 times 10 to the negative third meters, quantity squared, multiplied by the tensile strength of 500 times. 10 to the sixth Newtons per meter squared and me find a forced tension equaling 519.3 Newton's now to find the height above ground we can This would be according to this diagram and we can say that here. Now you gonna supply the sum of forces in the UAE direction. This is equaling two times the force tension sign of Fada minus and G this illegal zero because the system has translational equilibrium in the, um Why direction and so Fada is gonna equal arc sine of mg over two times the force tension and so we can solve fatal would equal arc sine and this would be the mass of 25 kilograms multiplied by 9.80 meters per second squared divided by two times 519.3 Newton's and we find that fate as equaling 13 points 64 degrees and to find the height above ground. Uh, we can use this diagram and say that tangent of data here with the equaling 3.0 meters minus h divided by 2.0 mucus and so H is equaling 3.0 meters minus 2.0 meters times tangent of 13.64 degrees. And so the height above ground H would be equaling approximately 2.5 meters. This would be our final answer. That is the end of the solution. Thank you for
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