00:01
This problem, a spring is compressed to the point that it stores 11 .5 joules of energy.
00:08
We first want to know, well, what is this block speed? if it's a 2 .5 kilogram block attached to this spring of 2 ,500 newton per meter spring constant, if it has that much energy, what is its velocity? what is its velocity after? where it was vf? all right.
00:30
So, well, its velocity is going to be given by this energy stored, and so all that energy, when it is converted into kinetic energy, we can solve for velocity.
00:44
Kinetic energy is given by one -half m v squared is equal to 11 .5 joules.
00:55
When you solve this equation for velocity, you get velocity is equal to the square root.
01:05
Of two times 11 .5 joules divided by the mass, which is 2 .5 kilograms.
01:22
That's a kilograms right there.
01:24
And that equals when you do it out 3 .03 meters per second.
01:34
Awesome.
01:37
The question also asks, what is the maximum acceleration? what's the maximum acceleration? and that would be at its most compressed.
01:48
So to do that, we need to figure out what is the force acting on the spring.
01:54
Well, force is given by, force of a spring is given by the spring constant times its position, its displacement, k times x...