00:01
So here the position of the air track glider, position of the function of time equals the amplitude multiplied by e raised to the negative time divided by two times tau, the time constant cosine of omega times t plus the phase constant phi not.
00:17
Here the time constant tau is equaling the mass over b, the damping constant, where the angular frequency is equaling the square root of the spring constant divided by the mass, minus this damping constant squared divided by 4m squared, extend the square root, and we can actually solve.
00:38
So this be a square root of 4 .0 newton's per meter.
00:43
This would be divided by 0 .250 kilograms minus 0 .0 .25 kilograms per second quantity squared.
00:56
This would be divided by 4 multiplied by 0 .015 kilograms per second quantity squared.
01:00
250 kilograms.
01:03
Again, quantity squared.
01:05
And we find then that omega is equaling 4 .0 radians per second.
01:12
And so the period t would be equaling to 2 pi over omega or 2 pi divided by 4 .0 radians per second...