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A 2.50 -mole quantity of NOCl was initially in a $1.50-\mathrm{L}$ reaction chamber at $400^{\circ} \mathrm{C} .$ After equilibrium was established, it was found that 28.0 percent of the NOCl had dissociated:$$2 \mathrm{NOCl}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Cl}_{2}(g)$$Calculate the equilibrium constant $K_{c}$ for the reaction.

$$K_{c}=0.0353$$

Chemistry 102

Chapter 14

Chemical Equilibrium

Amr Y.

August 13, 2021

2NO(g) + Cl2(g) Is 6.5x104 at 35?C. in a certain experiment, 2.0x10-2 mole of NO, 8.3X10-3 mole of Cl2, and 6.8 moles of NOCl are mixed in a 2.0-L flask. . In which direction will the system proceed to reach equilibrium?

Carleton College

Drexel University

Lectures

10:03

In thermodynamics, a state of thermodynamic equilibrium is a state in which a system is in thermal equilibrium with its surroundings. A system in thermodynamic equilibrium is in thermal equilibrium, mechanical equilibrium, electrical equilibrium, and chemical equilibrium. A system is in equilibrium when it is in thermal equilibrium with its surroundings.

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In chemistry, chemical equilibrium (also known as dynamic equilibrium) is a state of chemical stability in which the concentrations of the chemical substances do not change in the course of time due to their reaction with each other in a closed system. Chemical equilibrium is an example of dynamic equilibrium, a thermodynamic concept.

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A 2.50 -mole sample of NOC…

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A 2.00 mole quantity of NO…

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$1.25$ moles of NOCl were …

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So for the following problem, we want to find the equilibrium, constant value, Casey. So first, what we want to do for anything else is we were giving the moles of her reactant. So it's go ahead and convert that to the concentration value. And so we you are doing concentration of our reacted here. Now we know that we had 2.5 moles that was given to us. You are also given that the volume is 1.5 leaders. So that means the initial concentration over reacted is 1.667 Since we know that and we want to know what the equilibrium constant is first you want to find what the different concentrations of our products in reactors are at equilibrium. So when we're thinking of anything at equilibrium, we're going to want to see if we can make an ice table. So since we just found this starting concentration, her reactions, we put that here. We know that we had none of the products. Then for the change do a minus two x Here we have the two here do a positive two x here, the to here for a first product and then for the chlorine gas, did you? Just a positive excuse. There's only a one here. So for what? We haven't equilibrium. Now we have 1.667 minus two x a positive two x and in X. So we were told that we had 28% of our reactant that was reacted at equilibrium so we can go ahead and find what that amount reacted would be by doing 28% of the initial concentration, Maria, and it is equivalent to 0.4 66 eight. Then we can use this value to find X cause we know that that was the amount reacted. So two X is equal to 0.4 668 which means that eggs is equivalent to 0.2 three 34 So now that we know XTs go down a little bit, we are able to find the concentrations of our products and reactions at equilibrium. So at equilibrium, its first focus on a reactant, you know, from here we can dio 1.667 minus the two x that we found here. That was four, 668 So the concentration at equilibrium off our reactant is 1.2 and then looking at our first product, it was two X here, so we can do to times are X value, which is 0.2 three 34 She's equivalent to 0.4 668 We knew that because two X is what we had here. But I just wanted to show that now and then for our second in last product. Corinne, you know, that is just X. So we know it to be just what we found for the X value. Now that we know these concentrations that equilibrium, we are able to plug them in to be equilibrium. Constant equation, Casey. So we're going to dio our products so we have our first product raced. How many moles we have than our second product all over are reacting concentration, which we know to be 1.2, and we're going to raise that to the second power because that's how many moles we have balanced equation based on this tricky artery. So if we were to calculate this out, we can find that Casey is equivalent to 0.0 35 three

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