Question
A $25.0-\Omega$ bulb is connected across the terminals of a $12.0-\mathrm{V}$ battery having 3.50$\Omega$ of internal resistance. What percentage of the power of the battery is dissipated across the internal resistance and hence is not available to the bulb?
Step 1
The potential difference (V) can be expressed as $V = I(R + r)$, where I is the current, R is the resistance, and r is the internal resistance. Show more…
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