A 250.0 g sample of a white solid is known to be a mixture of KNO $_{3}, \mathrm{BaCl}_{2},$ and $\mathrm{NaCl}$ . When 100.0 $\mathrm{g}$ of this mixture is dissolved in water and allowed to react with excess $\mathrm{H}_{2} \mathrm{SO}_{4}$ 67.3 $\mathrm{g}$ of a white precipitate is collected. When the remaining 150.0 g of the mixture is dissolved in water and allowed to react with excess AgNO $_{3}, 197.6 \mathrm{g}$ of a second precipitate is collected.
(a) What are the formulas of the two precipitates?
(b) What is the mass of each substance in the original 250 g mixture?