00:01
So now we're going to work on the problem 61 from chapter 8.
00:07
In this problem, we're asked about how much perchloric acid would be required to titrate a certain volume and concentration of sodium hydroxide to reach the equivalent.
00:24
We know the amount of volume, but we want to know the concentration.
00:28
And then we're provided the reaction, which we can reproduce here.
00:34
So we have perchloric acid h .c .l .o .4 reacting with sodium hydroxide to produce water and n -a -sodium perchlorate, n -a -c -l -o -4.
00:52
Now, this reaction is important just so we can know the stoichiometric ratio between the reactants.
01:00
So we're given the volume and concentration of sodium hydroxide, so we can multiply those together to get the moles of sodium hydroxide.
01:12
So we have 0 .2 000 moles of nahoh per liter.
01:25
So we multiply by liters.
01:27
We get 0.
01:30
We have 22 .62 milliliters, so 0 .02262 liters...