00:01
The question states that we have 2 .56 .24 grams of alkaline metal chloride.
00:12
And because it is an alkaline metal, the molar ratio between the metal and chlorine should be one to one.
00:20
And when it reacts with silver nitrate, it forms a precipitate.
00:28
And we know that silver chloride does not dissolve in water.
00:33
So it will precipitate out of the solution plus the metal nitrate salt within the solution.
00:46
And from looking at the molar mass, we know that silver has molar mass of 107.
00:57
0 .868 gram per mole.
01:03
And we know chlorine has a molar weight of 35.
01:10
4, 5, 3 grams per mole.
01:17
And the total weight of silver nitrate from this reaction is 3 .03707 grams.
01:30
From here we know that the total weight of silver nitrogen is around 3 grams.
01:36
And by knowing the molar weight of both silver and chlorine we can calculate the exact gram amount of chlorine within the silver chloride precipitate...