The tape was found to be 30.01 m at the beginning and 30.026 m at the end. To find the average length, we calculate:
\[
\text{Average length} = \frac{30.01 \, \text{m} + 30.026 \, \text{m}}{2} = \frac{60.036 \, \text{m}}{2} = 30.018 \, \text{m}
\]
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