00:01
So for part a, we can say that bullet loses all kinetic energy as it is stopped by that block of ice.
00:16
So stopped by ice.
00:19
And we can say that thermal energy from bullet transfers to ice.
00:36
And this would be as the bullet cools from 30 degrees celsius to the final temperature.
00:42
Now, we could say that the kinetic energy plus thermal energy from bullet melts part of the ice.
01:13
And because not all of the ice melts, so when the bullet is embedded in this ice block, it's not, the entire ice block does not melt, of course.
01:23
So we can say that the final temperature of the bullet is zero degrees celsius because this would be the temperature of that ice.
01:43
So that would be the final temperature and this is a quick summary of the energy transformations that are in play here.
01:51
So we can then say that the total energy transferred from the bullet to the ice for part b, this would be the energy transferred would be.
02:04
Equal to the initial kinetic energy plus the mass of the bullet times the specific heat capacity of lead which is what the bullet is made out of multiplied by the absolute value of zero degrees celsius minus 30 degrees celsius and so we can then say that the energy transfer would be equaling one half times the mass of the bullet times the velocity initial squared plus the mass of the bullet the specific heat of lead multiplied by 30 degrees celsius.
02:43
And so we can then say that this would be one half multiplied by the mass of the bullet, 3 .00...