a-333-mathrmk-omega-resistor-is-connected-to-a-generator-with-a-maximum-voltage-of-241-mathrmv-find-

Question

A $3.33-\mathrm{k} \Omega$ resistor is connected to a generator with a maximum voltage of 241 $\mathrm{V} .$ Find (a) the average and (b) the maximum power
delivered to this circuit.

João Gabriel Alencar Caribé · Accepted Answer

in these questions are three points 33 kilo Holmes Resister is connected to a generator that can offer a maximum voltage off 241 votes in the first item. We have to calculate what is the average power. Deliver it to the circuit. So too complex the average power we use the following relation p a V is equals two v r. M s squared over our on v r amass A few guys, Remember is given by v r. A. Mass was close to remarks over square root of two. Then we have that the average power is equals. Two remarks square over to our and then bugging their values. We got 241 squared over two times three point authority tree times 10 Deterred. This is because off the kilo, these is the same as 10 to the third. And so we get that the average power. Deliver it Izzy course too. 8.72. What? In the second item, we have to calculate what is the maximum power delivered. So the maximum power delivery is given by Pete Much his equals two V marks squared over our and there&#x27;s a straightforward. We just have to put in the given values. So 241 squared over three 0.33 times, 10 to the third, and these is equals two 17 point 40 for once.

João Gabriel Alencar Caribé · Answer

the average power consumed by the circuit is given by TV. Is it close to I? Are you a mass squared? Times the resistance. So now we have to complete What is the area mass current on the circuit? To do that, we use almost law, which says that they are immensely voltage is it goes to the arguments correct times the impudence of that circuit. Then they are a mess. Current is equal studio demands voltage divided by the impudence before the average power is equals to the aromatics rotation squared, divided by the impedance squared Multiply it by the resistance. Now remember that Olympians in that circuit is equal to the square it off the resistance squared plus the capacity react osa squared. Then the average power is the course, too. The Ari mass squared, divided by the square root off R squared plus XY squared squared times are which is It goes to the ROMs squared times r squared plus XY squared under are and then remember also that Maxie, which is the capacity reactors, is the course to one divided by two pi times the frequency time, the capacitors and the reform we have. Is he close to 172. Squared times 6.3 times. Stand to the third squared plus to buy times 60 times, 2.5 times, 10 to the minus, six under one squared. And this is all under 6.3 times. Stand to the turn and these things approximately four point feeds to one. What&#x27;s

João Gabriel Alencar Caribé · Answer

in the first item. We have to evaluate the power factor of the circuit. So we have to evaluate the co sign other fees and the music goes to the resistance divided by BNP. This and in this case, the impudence has two contributions, one coming from the resistance and another one coming from they looked at us. So the feelings is it goes to the square it off squares plus the inductive reactors. Where&#x27;d they looked? Reactant is given by two quiet times the frequency times, the induct ins. No, we can plug in the values given by the problem in this equation and get the power factor. We choose the square root off two times, stand to the turns. There is a kilo there squared plus to pi times 1.55 Again there is a kilo times 292 merely squared. This is old under the resistance reaches two times 10 to return and these things approximately 0.5 seven 52 which we can for the approximate to 0.575 in the next item we have to complete. What is the average power consumers by that stir Great the average power is given by the are a mess voltage times the arguments current times the power factor. Now remember that there is a relation between the aromas voltage on the Aramis current and that relation is the following. The remans voltage is of course, to ari mass current. Multiply it biting Peters, then solving for the R. M s current, we get that the Aramis current is equals two The aromatase voltage divided by eating peanuts. No, the average power is then the remans voltage squared divided by they impede us and multiply it by the power factor and disease equals truth. A square root off the resistance is squared. Plus to buy f l squared under a square root under the aromatics voltage squared times the power factor This is just impedance which we have already calculated here. So we know just have to put in their values given by the problem on the power factor that we have completed before To get the following square root off two times 10 to the third squared plus to five times 1.55 time stand to deterred times 292 times 10 to the minus tree squared This is all under 20 points. Eight squared times the power factor, which is 0.575 and disease approximately 0.715 five, which we can write as 71.6. Really, What?

Salamat Ali · Answer

but a off the even problem. Um, we know from this relation that re maximum physical Thio We are a mess times they&#x27;re swearing off it too. From here we can write, but a that is a re max will be equal to our mess. Given is 1 20 times where route off too. This gives us remax off 1 70 year olds. I want to be, um Wi Max weekend right is from all those law are times I&#x27;m ex and from here I Max will be cool too. You called to 1 70 17 to do right by resistance, which is 1.5 times. Don&#x27;t our three year old homes. Um, excuse us there. I&#x27;m excellent. 0.11 in Pierre, look. See? Oh, we can find the I are in this by dividing I Max, I&#x27;m expe I screwed over to this. Is there a 0.11 in Pierre, If I buy skirt off to this gives us Ah, the current off our famous eight times dental baller minus to appear body we confined. Average power is equal to, um the We are in this square. Our miss were divided by the resistance so substituting values 1 20 Um, we have got a power. The re arm s off 1 20 So 1 20 square. Divided by resistance. 1.5 times. Don&#x27;t power three. This uses the power off 9.6 wars.

Khoobchandra Agrawal · Answer

in our series Off in Dr of Register on Capitol Components. Having the bed indoctrinates don&#x27;t really handy Carpets Tinto 1 40. No, no, Forget it. And the distance off. Chief it deal the letter Hasn&#x27;t Aramis bolted up? Want on people on frequency? 1.25 kilohertz. We have to Gallipoli Barber supplied by the generator B but poverty depicted in the register in our in order to see you No average power supplied by the source. The average off source is given. Bite I out of it the famous and do cross fight Bob, but consumed by register art Benry Ice. Where are Emmis? Into what? These two concepts we have to use be required the omelet frequency so we can measure now. Goodbye ever the window. 3.1 ft, 1.25 in tow. 10 to the power three Radian per second. So maybe you will get seven point a 5 ft and 10 to the power three Radian per second. We can fight the reappearance off. Inducted on Capitol as well. You re a paint off in The spirit is on me. Omega is seven. Went 85 ft 10 to the power three on Independence. It continually, Henry, let me check. So 20 in tow tend to be power my industry on solving it. It would be 1 57 0 Andrea prints off campus studies burn up on the way. I do see Omega is seven point it Fight foot she is given. See having the just be 1 14. I know on solving it you will get the get prints off campus. Turtle, be 909 No. Start solving trust. Able to fight the frayed relations between correction. You It would be stand up. Fight. Just give invite. Naturally. A prince of the circuit XL minus xy upon, huh? Except it&#x27;s one piece of it. XY is 90. You know, Night of the distance is 3 50 so we will get

Salamat Ali · Answer

But if the given problem I are a mess, Aramis, current in the resistance are mrs Given by we are mess divided by our from albums law The arm s we have won 20 times tempted by minus three divided by the resistance is 24 This gives us I are miss or five times dental More in history appear but maybe we can find we are miss We are a miss from the relation that is square root off a p average average times the resistance those of student your values for resistance an average p at 0.60 downs resistance which is 24 times tempted by our three This gives us Miata mus off 1 20 works.

Problem

A "75 -watt" lightbulb uses an average power of 7…

Problem 5 Easy Difficulty

A $3.33-\mathrm{k} \Omega$ resistor is connected to a generator with a maximum voltage of 241 $\mathrm{V} .$ Find (a) the average and (b) the maximum power
delivered to this circuit.

Answer

a) 8.72 $\mathrm{W}$
b) $[17.4 \mathrm{W}]$

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a) 8.72 $\mathrm{W}$b) $[17.4 \mathrm{W}]$

Physics

Christina K.

Liev B.

Marshall S.

Farnaz M.

Electric Charge

The Electric Force

James S. WalkerPhysics

Christina K.

Liev B.

Marshall S.

Farnaz M.

a) 8.72 $\mathrm{W}$
b) $[17.4 \mathrm{W}]$

James S. Walker

Physics