Question
A 3.49-rad/s ( $33 \frac{1}{3}$ rpm) record has a $5.00-\mathrm{kHz}$ tone cut in the groove. If the groove is located $0.100 \mathrm{m}$ from the center of the record (see drawing), what is the wavelength in the groove?
Step 1
100 m: v = ω r = (3.49 rad/s)(0.100 m) = 0.349 m/s. Show more…
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