Question
A $35-\Omega$ electric stove burner consumes $1.5 \mathrm{~kW}$ of power. At what voltage does it operate?
Step 1
We are given the power (P = 1.5 kW = 1500 W) and the resistance (R = 35 Ω). We need to find the voltage (V). Rearranging the formula for V, we get: V = sqrt(P * R) Show more…
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