Question
A 4.00 -M\Omega resistor and a $3.00-\mu \mathrm{F}$ capacitor are connected in series with a $12.0-\mathrm{V}$ power supply. (a) What is the time constant for the circuit? (b) Express the current in the circuit and the charge on the capacitor as functions of time.
Step 1
e., $T=RC$. Here, the resistance $R=4.00 M\Omega = 4 \times 10^6 \Omega$ and the capacitance $C=3.00 \mu F = 3 \times 10^{-6} F$. Substituting these values, we get \[T = RC = (4 \times 10^6 \Omega)(3 \times 10^{-6} F) = 12 s.\] Show more…
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