Question
A 4.22-g mixture of calcium chloride and sodium chloride was treated so that all of the calcium was converted to calcium carbonate. This product was then heated, converting it to $0.959 \mathrm{~g}$ pure calcium oxide. Calculate the mass percent of calcium chloride in the original mixture.
Step 1
We know that the molar mass of calcium oxide is 56.1 g/mol. So, we have: \[0.959 \, \text{g} \, \text{CaO} \times \frac{1 \, \text{mol} \, \text{CaO}}{56.1 \, \text{g} \, \text{CaO}} = 0.0171 \, \text{mol} \, \text{CaO}\] Show more…
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