00:01
So at the start of the circuit when we just connect the circuit into a full closed circuit, the capacitor has no charge, and therefore it acts like a short circuit.
00:23
That is it allows current to flow through without any resistance.
00:27
And therefore, the voltage drop across the capacitor.
00:36
Vc is zero.
00:39
The voltage drop across the resistor, on the other hand, takes up the entire emf of our battery.
00:52
It makes sense it is the only other component in our circuits, so we will take up the entire voltage source.
01:02
Then charge in the capacitor once again already mentioned that is zero, no charge.
01:07
The current through the resistor which you can use r equals to v over r should get a current 2 .0 327 appears and now we want to consider all of these values but when time has passed very long time has passed and the capacitor we assume to be fully charged so when it's fully charged now the capacitor acts like an open circuit.
02:05
It is an open circuit, acts like a broken wire, no current can slow past it...